소스 검색

fix: `frappe.log_error` arguments while capturing razorpay payment failures

pull/2/head
Rucha Mahabal 3 년 전
부모
커밋
70d63dcddf
1개의 변경된 파일3개의 추가작업 그리고 3개의 파일을 삭제
  1. +3
    -3
      payments/payment_gateways/doctype/razorpay_settings/razorpay_settings.py

+ 3
- 3
payments/payment_gateways/doctype/razorpay_settings/razorpay_settings.py 파일 보기

@@ -140,7 +140,7 @@ class RazorpaySettings(Document):
headers={"content-type": "application/json"}, headers={"content-type": "application/json"},
) )
if not resp.get("id"): if not resp.get("id"):
frappe.log_error(str(resp), "Razorpay Failed while creating subscription")
frappe.log_error(message=str(resp), title="Razorpay Failed while creating subscription")
except: except:
frappe.log_error(frappe.get_traceback()) frappe.log_error(frappe.get_traceback())
# failed # failed
@@ -179,7 +179,7 @@ class RazorpaySettings(Document):
frappe.flags.status = "created" frappe.flags.status = "created"
return kwargs return kwargs
else: else:
frappe.log_error(str(resp), "Razorpay Failed while creating subscription")
frappe.log_error(message=str(resp), title="Razorpay Failed while creating subscription")


except: except:
frappe.log_error(frappe.get_traceback()) frappe.log_error(frappe.get_traceback())
@@ -281,7 +281,7 @@ class RazorpaySettings(Document):
self.flags.status_changed_to = "Verified" self.flags.status_changed_to = "Verified"


else: else:
frappe.log_error(str(resp), "Razorpay Payment not authorized")
frappe.log_error(message=str(resp), title="Razorpay Payment not authorized")


except: except:
frappe.log_error(frappe.get_traceback()) frappe.log_error(frappe.get_traceback())


불러오는 중...
취소
저장